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Simplify directory_path

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This looked to be identical code to what `filename` used.
Remove the duplicated code by using the function instead.
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tcely 2024-12-10 00:05:58 -05:00 committed by GitHub
parent 40e48c9317
commit a4dc416ce8
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1 changed files with 1 additions and 4 deletions
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tubesync/sync/models.py
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@ -1291,10 +1291,7 @@ class Media(models.Model):
@property @property
def directory_path(self): def directory_path(self):
# Otherwise, create a suitable filename from the source media_format dirname = self.source.directory_path / self.filename
media_format = str(self.source.media_format)
media_details = self.format_dict
dirname = self.source.directory_path / media_format.format(**media_details)
return os.path.dirname(str(dirname)) return os.path.dirname(str(dirname))
@property @property